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1362003472957 is a prime number
BaseRepresentation
bin10011110100011101101…
…110111011001000111101
311211012120100211020012111
4103310131232323020331
5134303340342113312
62521410141134021
7200254500334201
oct23643556731075
94735510736174
101362003472957
114856934a9126
1219bb7025a311
139b58994668a
1449cc815cb01
15256674c48a7
hex13d1dbbb23d

1362003472957 has 2 divisors, whose sum is σ = 1362003472958. Its totient is φ = 1362003472956.

The previous prime is 1362003472937. The next prime is 1362003473021. The reversal of 1362003472957 is 7592743002631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1195099358436 + 166904114521 = 1093206^2 + 408539^2 .

It is a cyclic number.

It is not a de Polignac number, because 1362003472957 - 231 = 1359855989309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1362003472957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1362003472937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681001736478 + 681001736479.

It is an arithmetic number, because the mean of its divisors is an integer number (681001736479).

Almost surely, 21362003472957 is an apocalyptic number.

It is an amenable number.

1362003472957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1362003472957 is an equidigital number, since it uses as much as digits as its factorization.

1362003472957 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1905120, while the sum is 49.

The spelling of 1362003472957 in words is "one trillion, three hundred sixty-two billion, three million, four hundred seventy-two thousand, nine hundred fifty-seven".