136203516634343 has 4 divisors (see below), whose sum is σ = 136353026532768. Its totient is φ = 136054006735920.

The previous prime is 136203516634327. The next prime is 136203516634457. The reversal of 136203516634343 is 343436615302631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136203516634343 - 2⁴ = 136203516634327 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 136203516634291 and 136203516634300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (136203516634243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74754947846 + ... + 74754949667.

It is an arithmetic number, because the mean of its divisors is an integer number (34088256633192).

Almost surely, 2^{136203516634343} is an apocalyptic number.

136203516634343 is a deficient number, since it is larger than the sum of its proper divisors (149509898425).

136203516634343 is an equidigital number, since it uses as much as digits as its factorization.

136203516634343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149509898424.

The product of its (nonzero) digits is 8398080, while the sum is 50.

The spelling of 136203516634343 in words is "one hundred thirty-six trillion, two hundred three billion, five hundred sixteen million, six hundred thirty-four thousand, three hundred forty-three".