Base | Representation |
---|---|
bin | 111111011011001111… |
… | …0100001110011111101 |
3 | 111000120101120101011011 |
4 | 1332312132201303331 |
5 | 4212422043123201 |
6 | 142323311155221 |
7 | 12561204104605 |
oct | 1766636416375 |
9 | 430511511134 |
10 | 136205442301 |
11 | 5284546a845 |
12 | 22492b15b11 |
13 | cac86b1a96 |
14 | 68416b5c05 |
15 | 3822a2d151 |
hex | 1fb67a1cfd |
136205442301 has 2 divisors, whose sum is σ = 136205442302. Its totient is φ = 136205442300.
The previous prime is 136205442293. The next prime is 136205442349. The reversal of 136205442301 is 103244502631.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127430436676 + 8775005625 = 356974^2 + 93675^2 .
It is a cyclic number.
It is not a de Polignac number, because 136205442301 - 23 = 136205442293 is a prime.
It is a super-2 number, since 2×1362054423012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136205442601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68102721150 + 68102721151.
It is an arithmetic number, because the mean of its divisors is an integer number (68102721151).
Almost surely, 2136205442301 is an apocalyptic number.
It is an amenable number.
136205442301 is a deficient number, since it is larger than the sum of its proper divisors (1).
136205442301 is an equidigital number, since it uses as much as digits as its factorization.
136205442301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 136205442301 its reverse (103244502631), we get a palindrome (239449944932).
The spelling of 136205442301 in words is "one hundred thirty-six billion, two hundred five million, four hundred forty-two thousand, three hundred one".
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