Base | Representation |
---|---|
bin | 111111011011011000… |
… | …1111000000111111111 |
3 | 111000120202010001210211 |
4 | 1332312301320013333 |
5 | 4212424342430211 |
6 | 142324012013251 |
7 | 12561265161265 |
oct | 1766661700777 |
9 | 430522101724 |
10 | 136210514431 |
11 | 52848314592 |
12 | 22494761227 |
13 | cac9769644 |
14 | 6842236435 |
15 | 38231d0e21 |
hex | 1fb6c781ff |
136210514431 has 2 divisors, whose sum is σ = 136210514432. Its totient is φ = 136210514430.
The previous prime is 136210514411. The next prime is 136210514459. The reversal of 136210514431 is 134415012631.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136210514431 is a prime.
It is a super-2 number, since 2×1362105144312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 136210514393 and 136210514402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136210514411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68105257215 + 68105257216.
It is an arithmetic number, because the mean of its divisors is an integer number (68105257216).
Almost surely, 2136210514431 is an apocalyptic number.
136210514431 is a deficient number, since it is larger than the sum of its proper divisors (1).
136210514431 is an equidigital number, since it uses as much as digits as its factorization.
136210514431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The spelling of 136210514431 in words is "one hundred thirty-six billion, two hundred ten million, five hundred fourteen thousand, four hundred thirty-one".
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