Base | Representation |
---|---|
bin | 10011110100100100010… |
… | …010110100000000000111 |
3 | 11211012212000221102120011 |
4 | 103310210102310000013 |
5 | 134304102031403244 |
6 | 2521425112251051 |
7 | 200260305043462 |
oct | 23644422640007 |
9 | 4735760842504 |
10 | 1362113544199 |
11 | 48573a6492a1 |
12 | 19bba10a0a87 |
13 | 9b5a66a52a5 |
14 | 49cd8a122d9 |
15 | 25671eb8434 |
hex | 13d244b4007 |
1362113544199 has 2 divisors, whose sum is σ = 1362113544200. Its totient is φ = 1362113544198.
The previous prime is 1362113544149. The next prime is 1362113544223. The reversal of 1362113544199 is 9914453112631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1362113544199 - 239 = 812357730311 is a prime.
It is a super-2 number, since 2×13621135441992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1362113544149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681056772099 + 681056772100.
It is an arithmetic number, because the mean of its divisors is an integer number (681056772100).
Almost surely, 21362113544199 is an apocalyptic number.
1362113544199 is a deficient number, since it is larger than the sum of its proper divisors (1).
1362113544199 is an equidigital number, since it uses as much as digits as its factorization.
1362113544199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 699840, while the sum is 49.
The spelling of 1362113544199 in words is "one trillion, three hundred sixty-two billion, one hundred thirteen million, five hundred forty-four thousand, one hundred ninety-nine".
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