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136221031002545 = 527244206200509
BaseRepresentation
bin11110111110010001101110…
…001010011111000110110001
3122212022121021212101011000122
4132332101232022133012301
5120323321132414040140
61201415024442300025
740456434064560116
oct3676215612370661
9585277255334018
10136221031002545
113a44a0187a9315
121334066b7b7615
135b017850b2348
14258d1c125290d
1510b364cec8ab5
hex7be46e29f1b1

136221031002545 has 4 divisors (see below), whose sum is σ = 163465237203060. Its totient is φ = 108976824802032.

The previous prime is 136221031002493. The next prime is 136221031002569. The reversal of 136221031002545 is 545200130122631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 78277619231296 + 57943411771249 = 8847464^2 + 7612057^2 .

It is a cyclic number.

It is not a de Polignac number, because 136221031002545 - 28 = 136221031002289 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13622103100250 + ... + 13622103100259.

It is an arithmetic number, because the mean of its divisors is an integer number (40866309300765).

Almost surely, 2136221031002545 is an apocalyptic number.

It is an amenable number.

136221031002545 is a deficient number, since it is larger than the sum of its proper divisors (27244206200515).

136221031002545 is an equidigital number, since it uses as much as digits as its factorization.

136221031002545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27244206200514.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 136221031002545 in words is "one hundred thirty-six trillion, two hundred twenty-one billion, thirty-one million, two thousand, five hundred forty-five".

Divisors: 1 5 27244206200509 136221031002545