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136241113 is a prime number
BaseRepresentation
bin10000001111011…
…01111111011001
3100111100202200011
420013231333121
5234334203423
621304041521
73243013261
oct1007557731
9314322604
10136241113
116a9a4a68
12397632a1
13222c2458
14141467a1
15be62b0d
hex81edfd9

136241113 has 2 divisors, whose sum is σ = 136241114. Its totient is φ = 136241112.

The previous prime is 136241093. The next prime is 136241117. The reversal of 136241113 is 311142631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72369049 + 63872064 = 8507^2 + 7992^2 .

It is an emirp because it is prime and its reverse (311142631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 136241113 - 25 = 136241081 is a prime.

It is a super-3 number, since 3×1362411133 (a number of 25 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (136241117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68120556 + 68120557.

It is an arithmetic number, because the mean of its divisors is an integer number (68120557).

Almost surely, 2136241113 is an apocalyptic number.

It is an amenable number.

136241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

136241113 is an equidigital number, since it uses as much as digits as its factorization.

136241113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 432, while the sum is 22.

The square root of 136241113 is about 11672.2368464661. The cubic root of 136241113 is about 514.5600452883.

Adding to 136241113 its reverse (311142631), we get a palindrome (447383744).

The spelling of 136241113 in words is "one hundred thirty-six million, two hundred forty-one thousand, one hundred thirteen".