Base | Representation |
---|---|
bin | 11001011000001001… |
… | …11110011010101111 |
3 | 1022011111201102012220 |
4 | 30230010332122233 |
5 | 210400321404011 |
6 | 10131534130423 |
7 | 661424343246 |
oct | 145404763257 |
9 | 38144642186 |
10 | 13624403631 |
11 | 5861691113 |
12 | 2782950a13 |
13 | 13918631c7 |
14 | 93366595d |
15 | 54b190506 |
hex | 32c13e6af |
13624403631 has 8 divisors (see below), whose sum is σ = 18190323840. Its totient is φ = 9070709592.
The previous prime is 13624403629. The next prime is 13624403641. The reversal of 13624403631 is 13630442631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13624403631 - 21 = 13624403629 is a prime.
It is a super-2 number, since 2×136244036312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13624403592 and 13624403601.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13624403641) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3053941 + ... + 3058398.
It is an arithmetic number, because the mean of its divisors is an integer number (2273790480).
Almost surely, 213624403631 is an apocalyptic number.
13624403631 is a deficient number, since it is larger than the sum of its proper divisors (4565920209).
13624403631 is an equidigital number, since it uses as much as digits as its factorization.
13624403631 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6113085.
The product of its (nonzero) digits is 31104, while the sum is 33.
The spelling of 13624403631 in words is "thirteen billion, six hundred twenty-four million, four hundred three thousand, six hundred thirty-one".
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