Base | Representation |
---|---|
bin | 111111011100101010… |
… | …1111011100100101101 |
3 | 111000200202000222121002 |
4 | 1332321111323210231 |
5 | 4213021400121143 |
6 | 142332145450045 |
7 | 12562326545411 |
oct | 1767125734455 |
9 | 430622028532 |
10 | 136253520173 |
11 | 5286a618421 |
12 | 224a7040925 |
13 | cb05646324 |
14 | 6847c2cd41 |
15 | 3826d785b8 |
hex | 1fb957b92d |
136253520173 has 2 divisors, whose sum is σ = 136253520174. Its totient is φ = 136253520172.
The previous prime is 136253519993. The next prime is 136253520199. The reversal of 136253520173 is 371025352631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 134070948649 + 2182571524 = 366157^2 + 46718^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136253520173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136253520673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68126760086 + 68126760087.
It is an arithmetic number, because the mean of its divisors is an integer number (68126760087).
Almost surely, 2136253520173 is an apocalyptic number.
It is an amenable number.
136253520173 is a deficient number, since it is larger than the sum of its proper divisors (1).
136253520173 is an equidigital number, since it uses as much as digits as its factorization.
136253520173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 38.
The spelling of 136253520173 in words is "one hundred thirty-six billion, two hundred fifty-three million, five hundred twenty thousand, one hundred seventy-three".
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