Search a number
-
+
136264745753 is a prime number
BaseRepresentation
bin111111011101000000…
…0110000001100011001
3111000201112011022012022
41332322000300030121
54213032233331003
6142333230224225
712562524141143
oct1767200601431
9430645138168
10136264745753
1152875995364
12224aa955075
13cb07a76996
146849511c93
153827d44738
hex1fba030319

136264745753 has 2 divisors, whose sum is σ = 136264745754. Its totient is φ = 136264745752.

The previous prime is 136264745677. The next prime is 136264745759. The reversal of 136264745753 is 357547462631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119544445504 + 16720300249 = 345752^2 + 129307^2 .

It is a cyclic number.

It is not a de Polignac number, because 136264745753 - 220 = 136263697177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 136264745695 and 136264745704.

It is not a weakly prime, because it can be changed into another prime (136264745759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68132372876 + 68132372877.

It is an arithmetic number, because the mean of its divisors is an integer number (68132372877).

Almost surely, 2136264745753 is an apocalyptic number.

It is an amenable number.

136264745753 is a deficient number, since it is larger than the sum of its proper divisors (1).

136264745753 is an equidigital number, since it uses as much as digits as its factorization.

136264745753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12700800, while the sum is 53.

The spelling of 136264745753 in words is "one hundred thirty-six billion, two hundred sixty-four million, seven hundred forty-five thousand, seven hundred fifty-three".