1362731143441 has 4 divisors (see below), whose sum is σ = 1362755280384. Its totient is φ = 1362707006500.

The previous prime is 1362731143429. The next prime is 1362731143469. The reversal of 1362731143441 is 1443411372631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1362731143441 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1362731143394 and 1362731143403.

It is not an unprimeable number, because it can be changed into a prime (1362731143481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11983585 + ... + 12096766.

It is an arithmetic number, because the mean of its divisors is an integer number (340688820096).

Almost surely, 2^{1362731143441} is an apocalyptic number.

It is an amenable number.

1362731143441 is a deficient number, since it is larger than the sum of its proper divisors (24136943).

1362731143441 is an equidigital number, since it uses as much as digits as its factorization.

1362731143441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24136942.

The product of its digits is 145152, while the sum is 40.

The spelling of 1362731143441 in words is "one trillion, three hundred sixty-two billion, seven hundred thirty-one million, one hundred forty-three thousand, four hundred forty-one".