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136303946047207 is a prime number
BaseRepresentation
bin11110111111011110111100…
…010010010001111011100111
3122212121112022100122211112201
4132333132330102101323213
5120331200440142002312
61201521100211355331
740465430564042161
oct3677367422217347
9585545270584481
10136303946047207
113a4811a711a614
121335474b8b2b47
135b0953a124953
1425932091db931
1510b58a2359557
hex7bf7bc491ee7

136303946047207 has 2 divisors, whose sum is σ = 136303946047208. Its totient is φ = 136303946047206.

The previous prime is 136303946047189. The next prime is 136303946047223. The reversal of 136303946047207 is 702740649303631.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136303946047207 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136303946347207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68151973023603 + 68151973023604.

It is an arithmetic number, because the mean of its divisors is an integer number (68151973023604).

Almost surely, 2136303946047207 is an apocalyptic number.

136303946047207 is a deficient number, since it is larger than the sum of its proper divisors (1).

136303946047207 is an equidigital number, since it uses as much as digits as its factorization.

136303946047207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13716864, while the sum is 55.

The spelling of 136303946047207 in words is "one hundred thirty-six trillion, three hundred three billion, nine hundred forty-six million, forty-seven thousand, two hundred seven".