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1363127040 = 283251131347
BaseRepresentation
bin101000100111111…
…1010101100000000
310111222222000202200
41101033322230000
510242430031130
6343132313200
745531250212
oct12117725400
93458860680
101363127040
1163a4a4580
12320612800
1318953b362
14cd0745b2
157ea0e760
hex513fab00

1363127040 has 432 divisors, whose sum is σ = 5326304256. Its totient is φ = 318873600.

The previous prime is 1363127033. The next prime is 1363127053. The reversal of 1363127040 is 407213631.

1363127040 is a `hidden beast` number, since 1 + 3 + 631 + 27 + 0 + 4 + 0 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 1363126995 and 1363127013.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3928147 + ... + 3928493.

It is an arithmetic number, because the mean of its divisors is an integer number (12329408).

Almost surely, 21363127040 is an apocalyptic number.

1363127040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1363127040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2663152128).

1363127040 is an abundant number, since it is smaller than the sum of its proper divisors (3963177216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1363127040 is a wasteful number, since it uses less digits than its factorization.

1363127040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 416 (or 399 counting only the distinct ones).

The product of its (nonzero) digits is 3024, while the sum is 27.

The square root of 1363127040 is about 36920.5503750960. The cubic root of 1363127040 is about 1108.7801549393.

The spelling of 1363127040 in words is "one billion, three hundred sixty-three million, one hundred twenty-seven thousand, forty".