136333005024331 has 4 divisors (see below), whose sum is σ = 144352593555192. Its totient is φ = 128313416493472.

The previous prime is 136333005024137. The next prime is 136333005024373. The reversal of 136333005024331 is 133420500333631.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 136333005024331 - 2¹¹ = 136333005022283 is a prime.

It is a super-4 number, since 4×136333005024331⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (136333005124331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4009794265405 + ... + 4009794265438.

It is an arithmetic number, because the mean of its divisors is an integer number (36088148388798).

Almost surely, 2^{136333005024331} is an apocalyptic number.

136333005024331 is a deficient number, since it is larger than the sum of its proper divisors (8019588530861).

136333005024331 is an equidigital number, since it uses as much as digits as its factorization.

136333005024331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8019588530860.

The product of its (nonzero) digits is 174960, while the sum is 37.

Adding to 136333005024331 its reverse (133420500333631), we get a palindrome (269753505357962).

The spelling of 136333005024331 in words is "one hundred thirty-six trillion, three hundred thirty-three billion, five million, twenty-four thousand, three hundred thirty-one".