Base | Representation |
---|---|
bin | 10011110101110100000… |
… | …101000010110011100111 |
3 | 11211100022022200201112012 |
4 | 103311310011002303213 |
5 | 134314322220041403 |
6 | 2522210010344435 |
7 | 200335420506014 |
oct | 23656405026347 |
9 | 4740268621465 |
10 | 1363452112103 |
11 | 486267199164 |
12 | 1a02b542b11b |
13 | 9b75aac4cc3 |
14 | 49dc46d270b |
15 | 256ee775ed8 |
hex | 13d74142ce7 |
1363452112103 has 8 divisors (see below), whose sum is σ = 1363985611200. Its totient is φ = 1362918709600.
The previous prime is 1363452112093. The next prime is 1363452112111. The reversal of 1363452112103 is 3012112543631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1363452112103 - 234 = 1346272242919 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1363452112103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1363452112303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40505426 + ... + 40539072.
It is an arithmetic number, because the mean of its divisors is an integer number (170498201400).
Almost surely, 21363452112103 is an apocalyptic number.
1363452112103 is a deficient number, since it is larger than the sum of its proper divisors (533499097).
1363452112103 is a wasteful number, since it uses less digits than its factorization.
1363452112103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48297.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 1363452112103 its reverse (3012112543631), we get a palindrome (4375564655734).
The spelling of 1363452112103 in words is "one trillion, three hundred sixty-three billion, four hundred fifty-two million, one hundred twelve thousand, one hundred three".
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