Search a number
-
+
136397262401 is a prime number
BaseRepresentation
bin111111100000111101…
…0010000111001000001
3111001001202111211212022
41333001322100321001
54213320144344101
6142354322411225
712566023413101
oct1770172207101
9431052454768
10136397262401
1152933776054
1222527200b15
13cb29363aba
14685cd69201
1538347bda1b
hex1fc1e90e41

136397262401 has 2 divisors, whose sum is σ = 136397262402. Its totient is φ = 136397262400.

The previous prime is 136397262343. The next prime is 136397262403. The reversal of 136397262401 is 104262793631.

It is a Cunningham number, because it is equal to 3693202+1.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136397262400 + 1 = 369320^2 + 1^2 .

It is a cyclic number.

It is not a de Polignac number, because 136397262401 - 214 = 136397246017 is a prime.

It is a Sophie Germain prime.

Together with 136397262403, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (136397262403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68198631200 + 68198631201.

It is an arithmetic number, because the mean of its divisors is an integer number (68198631201).

Almost surely, 2136397262401 is an apocalyptic number.

It is an amenable number.

136397262401 is a deficient number, since it is larger than the sum of its proper divisors (1).

136397262401 is an equidigital number, since it uses as much as digits as its factorization.

136397262401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 44.

The spelling of 136397262401 in words is "one hundred thirty-six billion, three hundred ninety-seven million, two hundred sixty-two thousand, four hundred one".