Base | Representation |
---|---|
bin | 10011110110010110001… |
… | …000001100101011011101 |
3 | 11211101210010121100020121 |
4 | 103312112020030223131 |
5 | 134322004440124232 |
6 | 2522342414314541 |
7 | 200355525203245 |
oct | 23662610145335 |
9 | 4741703540217 |
10 | 1364023364317 |
11 | 48652a6a1429 |
12 | 1a04347b8a51 |
13 | 9b81c266873 |
14 | 4a03a514b25 |
15 | 257349b5d97 |
hex | 13d9620cadd |
1364023364317 has 2 divisors, whose sum is σ = 1364023364318. Its totient is φ = 1364023364316.
The previous prime is 1364023364281. The next prime is 1364023364339. The reversal of 1364023364317 is 7134633204631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1361821314841 + 2202049476 = 1166971^2 + 46926^2 .
It is a cyclic number.
It is not a de Polignac number, because 1364023364317 - 211 = 1364023362269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1364023364377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682011682158 + 682011682159.
It is an arithmetic number, because the mean of its divisors is an integer number (682011682159).
Almost surely, 21364023364317 is an apocalyptic number.
It is an amenable number.
1364023364317 is a deficient number, since it is larger than the sum of its proper divisors (1).
1364023364317 is an equidigital number, since it uses as much as digits as its factorization.
1364023364317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 653184, while the sum is 43.
Adding to 1364023364317 its reverse (7134633204631), we get a palindrome (8498656568948).
The spelling of 1364023364317 in words is "one trillion, three hundred sixty-four billion, twenty-three million, three hundred sixty-four thousand, three hundred seventeen".
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