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136404635186893 is a prime number
BaseRepresentation
bin11111000000111100101101…
…110100110111011011001101
3122212222011012120001002201111
4133000330231310313123031
5120334323143101440033
61202035231353212021
740505624006440243
oct3700745564673315
9585864176032644
10136404635186893
113a50a976557547
1213370170401011
135b15b95640448
14259803b9aa793
1510b82e6d1d7cd
hex7c0f2dd376cd

136404635186893 has 2 divisors, whose sum is σ = 136404635186894. Its totient is φ = 136404635186892.

The previous prime is 136404635186881. The next prime is 136404635186899. The reversal of 136404635186893 is 398681536404631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136403665923204 + 969263689 = 11679198^2 + 31133^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136404635186893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136404635186899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68202317593446 + 68202317593447.

It is an arithmetic number, because the mean of its divisors is an integer number (68202317593447).

Almost surely, 2136404635186893 is an apocalyptic number.

It is an amenable number.

136404635186893 is a deficient number, since it is larger than the sum of its proper divisors (1).

136404635186893 is an equidigital number, since it uses as much as digits as its factorization.

136404635186893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 268738560, while the sum is 67.

The spelling of 136404635186893 in words is "one hundred thirty-six trillion, four hundred four billion, six hundred thirty-five million, one hundred eighty-six thousand, eight hundred ninety-three".