Base | Representation |
---|---|
bin | 111111100001011011… |
… | …1110111110001010111 |
3 | 111001002212220100112212 |
4 | 1333002313313301113 |
5 | 4213333313144224 |
6 | 142400100504035 |
7 | 12566310605543 |
oct | 1770267676127 |
9 | 431085810485 |
10 | 136413412439 |
11 | 529418a6897 |
12 | 225306ab01b |
13 | cb2c7c9a35 |
14 | 6861170a23 |
15 | 3835e0dd0e |
hex | 1fc2df7c57 |
136413412439 has 2 divisors, whose sum is σ = 136413412440. Its totient is φ = 136413412438.
The previous prime is 136413412411. The next prime is 136413412501. The reversal of 136413412439 is 934214314631.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 136413412439 - 228 = 136144976983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 136413412396 and 136413412405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136413402439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68206706219 + 68206706220.
It is an arithmetic number, because the mean of its divisors is an integer number (68206706220).
Almost surely, 2136413412439 is an apocalyptic number.
136413412439 is a deficient number, since it is larger than the sum of its proper divisors (1).
136413412439 is an equidigital number, since it uses as much as digits as its factorization.
136413412439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 186624, while the sum is 41.
The spelling of 136413412439 in words is "one hundred thirty-six billion, four hundred thirteen million, four hundred twelve thousand, four hundred thirty-nine".
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