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13642565341313 is a prime number
BaseRepresentation
bin1100011010000110100001…
…0000101101000010000001
31210022012211211112221222102
43012201220100231002001
53242004433211410223
645003150305520145
72605433326030406
oct306415020550201
953265754487872
1013642565341313
11438a863524217
12164402b643055
1377c646cc47cc
143524374562ad
15189d1b322928
hexc686842d081

13642565341313 has 2 divisors, whose sum is σ = 13642565341314. Its totient is φ = 13642565341312.

The previous prime is 13642565341291. The next prime is 13642565341331. The reversal of 13642565341313 is 31314356524631.

Together with next prime (13642565341331) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10972570125169 + 2669995216144 = 3312487^2 + 1634012^2 .

It is a cyclic number.

It is not a de Polignac number, because 13642565341313 - 216 = 13642565275777 is a prime.

It is a super-2 number, since 2×136425653413132 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13642565341393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821282670656 + 6821282670657.

It is an arithmetic number, because the mean of its divisors is an integer number (6821282670657).

Almost surely, 213642565341313 is an apocalyptic number.

It is an amenable number.

13642565341313 is a deficient number, since it is larger than the sum of its proper divisors (1).

13642565341313 is an equidigital number, since it uses as much as digits as its factorization.

13642565341313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2332800, while the sum is 47.

The spelling of 13642565341313 in words is "thirteen trillion, six hundred forty-two billion, five hundred sixty-five million, three hundred forty-one thousand, three hundred thirteen".