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13642565341331 is a prime number
BaseRepresentation
bin1100011010000110100001…
…0000101101000010010011
31210022012211211112222000002
43012201220100231002103
53242004433211410311
645003150305520215
72605433326030433
oct306415020550223
953265754488002
1013642565341331
11438a863524233
12164402b64306b
1377c646cc4814
143524374562c3
15189d1b32293b
hexc686842d093

13642565341331 has 2 divisors, whose sum is σ = 13642565341332. Its totient is φ = 13642565341330.

The previous prime is 13642565341313. The next prime is 13642565341381. The reversal of 13642565341331 is 13314356524631.

Together with previous prime (13642565341313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13642565341331 - 230 = 13641491599507 is a prime.

It is a super-2 number, since 2×136425653413312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13642565341381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821282670665 + 6821282670666.

It is an arithmetic number, because the mean of its divisors is an integer number (6821282670666).

Almost surely, 213642565341331 is an apocalyptic number.

13642565341331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13642565341331 is an equidigital number, since it uses as much as digits as its factorization.

13642565341331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2332800, while the sum is 47.

The spelling of 13642565341331 in words is "thirteen trillion, six hundred forty-two billion, five hundred sixty-five million, three hundred forty-one thousand, three hundred thirty-one".