Base | Representation |
---|---|
bin | 11111000001010100011110… |
… | …111111111000110110010101 |
3 | 122220001121002011101000010020 |
4 | 133001110132333320312111 |
5 | 120340232424443044340 |
6 | 1202055052025415353 |
7 | 40510516311605043 |
oct | 3701243677706625 |
9 | 586047064330106 |
10 | 136430156221845 |
11 | 3a51a782507872 |
12 | 133750b333a559 |
13 | 5b18401ab5265 |
14 | 259937d223393 |
15 | 10b8cdc6119d0 |
hex | 7c151eff8d95 |
136430156221845 has 16 divisors (see below), whose sum is σ = 218288571844992. Its totient is φ = 72762642688320.
The previous prime is 136430156221837. The next prime is 136430156221871. The reversal of 136430156221845 is 548122651034631.
It is not a de Polignac number, because 136430156221845 - 23 = 136430156221837 is a prime.
It is a super-2 number, since 2×1364301562218452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4398360 + ... + 17094030.
It is an arithmetic number, because the mean of its divisors is an integer number (13643035740312).
Almost surely, 2136430156221845 is an apocalyptic number.
136430156221845 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
136430156221845 is a deficient number, since it is larger than the sum of its proper divisors (81858415623147).
136430156221845 is a wasteful number, since it uses less digits than its factorization.
136430156221845 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13412092.
The product of its (nonzero) digits is 4147200, while the sum is 51.
The spelling of 136430156221845 in words is "one hundred thirty-six trillion, four hundred thirty billion, one hundred fifty-six million, two hundred twenty-one thousand, eight hundred forty-five".
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