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13643153401 is a prime number
BaseRepresentation
bin11001011010011000…
…11111111111111001
31022012211000000001211
430231030133333321
5210420121402101
610133444043121
7662042614303
oct145514377771
938184000054
1013643153401
115871228099
1227890934a1
1313956c9547
14935d46973
1554cb45c51
hex32d31fff9

13643153401 has 2 divisors, whose sum is σ = 13643153402. Its totient is φ = 13643153400.

The previous prime is 13643153393. The next prime is 13643153411. The reversal of 13643153401 is 10435134631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13557109225 + 86044176 = 116435^2 + 9276^2 .

It is an emirp because it is prime and its reverse (10435134631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13643153401 - 23 = 13643153393 is a prime.

It is a super-2 number, since 2×136431534012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13643153411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821576700 + 6821576701.

It is an arithmetic number, because the mean of its divisors is an integer number (6821576701).

Almost surely, 213643153401 is an apocalyptic number.

It is an amenable number.

13643153401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13643153401 is an equidigital number, since it uses as much as digits as its factorization.

13643153401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 31.

The spelling of 13643153401 in words is "thirteen billion, six hundred forty-three million, one hundred fifty-three thousand, four hundred one".