Base | Representation |
---|---|
bin | 11001011010011010… |
… | …10001000100100111 |
3 | 1022012211101012210111 |
4 | 30231031101010213 |
5 | 210420144320112 |
6 | 10133452233451 |
7 | 662044412314 |
oct | 145515210447 |
9 | 38184335714 |
10 | 13643354407 |
11 | 5871355111 |
12 | 278916b887 |
13 | 1395769b97 |
14 | 935d99d0b |
15 | 54cb855a7 |
hex | 32d351127 |
13643354407 has 2 divisors, whose sum is σ = 13643354408. Its totient is φ = 13643354406.
The previous prime is 13643354371. The next prime is 13643354419. The reversal of 13643354407 is 70445334631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13643354407 - 27 = 13643354279 is a prime.
It is a super-2 number, since 2×136433544072 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13643354407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13643354447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821677203 + 6821677204.
It is an arithmetic number, because the mean of its divisors is an integer number (6821677204).
Almost surely, 213643354407 is an apocalyptic number.
13643354407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13643354407 is an equidigital number, since it uses as much as digits as its factorization.
13643354407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 362880, while the sum is 40.
The spelling of 13643354407 in words is "thirteen billion, six hundred forty-three million, three hundred fifty-four thousand, four hundred seven".
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