Base | Representation |
---|---|
bin | 11111000001100000101111… |
… | …010101110101111101000111 |
3 | 122220002212001020112011200101 |
4 | 133001200233111311331013 |
5 | 120340441402210031003 |
6 | 1202105105502424531 |
7 | 40511463356212501 |
oct | 3701405725657507 |
9 | 586085036464611 |
10 | 136443315314503 |
11 | 3a52531547495a |
12 | 13377766292147 |
13 | 5b1971b11a712 |
14 | 2599c6ab62d71 |
15 | 10b930c9dc11d |
hex | 7c182f575f47 |
136443315314503 has 2 divisors, whose sum is σ = 136443315314504. Its totient is φ = 136443315314502.
The previous prime is 136443315314459. The next prime is 136443315314521. The reversal of 136443315314503 is 305413513344631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136443315314503 - 241 = 134244292058951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136443315314573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68221657657251 + 68221657657252.
It is an arithmetic number, because the mean of its divisors is an integer number (68221657657252).
Almost surely, 2136443315314503 is an apocalyptic number.
136443315314503 is a deficient number, since it is larger than the sum of its proper divisors (1).
136443315314503 is an equidigital number, since it uses as much as digits as its factorization.
136443315314503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2332800, while the sum is 46.
The spelling of 136443315314503 in words is "one hundred thirty-six trillion, four hundred forty-three billion, three hundred fifteen million, three hundred fourteen thousand, five hundred three".
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