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1364433360313 is a prime number
BaseRepresentation
bin10011110110101110100…
…100001101010110111001
311211102211201002022000111
4103312232210031112321
5134323324420012223
62522451222104321
7200401634126662
oct23665644152671
94742751068014
101364433360313
114867200744a1
121a0529b7b0a1
139b886197c4a
144a078b5c369
152575a9a130d
hex13dae90d5b9

1364433360313 has 2 divisors, whose sum is σ = 1364433360314. Its totient is φ = 1364433360312.

The previous prime is 1364433360259. The next prime is 1364433360341. The reversal of 1364433360313 is 3130633344631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1083758035369 + 280675324944 = 1041037^2 + 529788^2 .

It is a cyclic number.

It is not a de Polignac number, because 1364433360313 - 229 = 1363896489401 is a prime.

It is not a weakly prime, because it can be changed into another prime (1364433360343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682216680156 + 682216680157.

It is an arithmetic number, because the mean of its divisors is an integer number (682216680157).

Almost surely, 21364433360313 is an apocalyptic number.

It is an amenable number.

1364433360313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1364433360313 is an equidigital number, since it uses as much as digits as its factorization.

1364433360313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 419904, while the sum is 40.

The spelling of 1364433360313 in words is "one trillion, three hundred sixty-four billion, four hundred thirty-three million, three hundred sixty thousand, three hundred thirteen".