Base | Representation |
---|---|
bin | 10011110110101110100… |
… | …100001101010110111001 |
3 | 11211102211201002022000111 |
4 | 103312232210031112321 |
5 | 134323324420012223 |
6 | 2522451222104321 |
7 | 200401634126662 |
oct | 23665644152671 |
9 | 4742751068014 |
10 | 1364433360313 |
11 | 4867200744a1 |
12 | 1a0529b7b0a1 |
13 | 9b886197c4a |
14 | 4a078b5c369 |
15 | 2575a9a130d |
hex | 13dae90d5b9 |
1364433360313 has 2 divisors, whose sum is σ = 1364433360314. Its totient is φ = 1364433360312.
The previous prime is 1364433360259. The next prime is 1364433360341. The reversal of 1364433360313 is 3130633344631.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1083758035369 + 280675324944 = 1041037^2 + 529788^2 .
It is a cyclic number.
It is not a de Polignac number, because 1364433360313 - 229 = 1363896489401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1364433360343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682216680156 + 682216680157.
It is an arithmetic number, because the mean of its divisors is an integer number (682216680157).
Almost surely, 21364433360313 is an apocalyptic number.
It is an amenable number.
1364433360313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1364433360313 is an equidigital number, since it uses as much as digits as its factorization.
1364433360313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 419904, while the sum is 40.
The spelling of 1364433360313 in words is "one trillion, three hundred sixty-four billion, four hundred thirty-three million, three hundred sixty thousand, three hundred thirteen".
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