Base | Representation |
---|---|
bin | 11111000001100011101110… |
… | …101100010001111101010111 |
3 | 122220010011022222022211201020 |
4 | 133001203232230101331113 |
5 | 120341014441031112011 |
6 | 1202110400223132223 |
7 | 40511636050445526 |
oct | 3701435654217527 |
9 | 586104288284636 |
10 | 136446525644631 |
11 | 3a526712633454 |
12 | 13378301444073 |
13 | 5b19b10265147 |
14 | 259a09327a4bd |
15 | 10b944977b006 |
hex | 7c18eeb11f57 |
136446525644631 has 4 divisors (see below), whose sum is σ = 181928700859512. Its totient is φ = 90964350429752.
The previous prime is 136446525644573. The next prime is 136446525644713.
136446525644631 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136446525644631 - 227 = 136446391426903 is a prime.
It is a super-2 number, since 2×1364465256446312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136446525644531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22741087607436 + ... + 22741087607441.
It is an arithmetic number, because the mean of its divisors is an integer number (45482175214878).
Almost surely, 2136446525644631 is an apocalyptic number.
136446525644631 is a deficient number, since it is larger than the sum of its proper divisors (45482175214881).
136446525644631 is an equidigital number, since it uses as much as digits as its factorization.
136446525644631 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45482175214880.
The product of its digits is 149299200, while the sum is 60.
The spelling of 136446525644631 in words is "one hundred thirty-six trillion, four hundred forty-six billion, five hundred twenty-five million, six hundred forty-four thousand, six hundred thirty-one".
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