Base | Representation |
---|---|
bin | 11001011010101010… |
… | …10001110001101001 |
3 | 1022012222022220111112 |
4 | 30231111101301221 |
5 | 210421214020231 |
6 | 10134005240105 |
7 | 662101310003 |
oct | 145525216151 |
9 | 38188286445 |
10 | 13645454441 |
11 | 5872559983 |
12 | 2789a03035 |
13 | 13960239c8 |
14 | 936385373 |
15 | 54ce4c92b |
hex | 32d551c69 |
13645454441 has 2 divisors, whose sum is σ = 13645454442. Its totient is φ = 13645454440.
The previous prime is 13645454393. The next prime is 13645454453. The reversal of 13645454441 is 14445454631.
13645454441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9447062416 + 4198392025 = 97196^2 + 64795^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13645454441 is a prime.
It is not a weakly prime, because it can be changed into another prime (13645454491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822727220 + 6822727221.
It is an arithmetic number, because the mean of its divisors is an integer number (6822727221).
Almost surely, 213645454441 is an apocalyptic number.
It is an amenable number.
13645454441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13645454441 is an equidigital number, since it uses as much as digits as its factorization.
13645454441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 460800, while the sum is 41.
The spelling of 13645454441 in words is "thirteen billion, six hundred forty-five million, four hundred fifty-four thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •