Base | Representation |
---|---|
bin | 11001011010101011… |
… | …00111101011001001 |
3 | 1022012222111110112121 |
4 | 30231111213223021 |
5 | 210421224403022 |
6 | 10134011211241 |
7 | 662102132341 |
oct | 145525475311 |
9 | 38188443477 |
10 | 13645544137 |
11 | 5872610305 |
12 | 2789a46b21 |
13 | 1396055794 |
14 | 9363a9d21 |
15 | 54ce692c7 |
hex | 32d567ac9 |
13645544137 has 2 divisors, whose sum is σ = 13645544138. Its totient is φ = 13645544136.
The previous prime is 13645544119. The next prime is 13645544177. The reversal of 13645544137 is 73144554631.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13480138816 + 165405321 = 116104^2 + 12861^2 .
It is a cyclic number.
It is not a de Polignac number, because 13645544137 - 223 = 13637155529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13645544093 and 13645544102.
It is not a weakly prime, because it can be changed into another prime (13645544177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6822772068 + 6822772069.
It is an arithmetic number, because the mean of its divisors is an integer number (6822772069).
Almost surely, 213645544137 is an apocalyptic number.
It is an amenable number.
13645544137 is a deficient number, since it is larger than the sum of its proper divisors (1).
13645544137 is an equidigital number, since it uses as much as digits as its factorization.
13645544137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 604800, while the sum is 43.
The spelling of 13645544137 in words is "thirteen billion, six hundred forty-five million, five hundred forty-four thousand, one hundred thirty-seven".
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