13645566547117 has 4 divisors (see below), whose sum is σ = 13645576227580. Its totient is φ = 13645556866656.

The previous prime is 13645566547073. The next prime is 13645566547177. The reversal of 13645566547117 is 71174566554631.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 2955713969961 + 10689852577156 = 1719219^2 + 3269534^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13645566547117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13645566547177) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2271378 + ... + 5696515.

It is an arithmetic number, because the mean of its divisors is an integer number (3411394056895).

Almost surely, 2^{13645566547117} is an apocalyptic number.

It is an amenable number.

13645566547117 is a deficient number, since it is larger than the sum of its proper divisors (9680463).

13645566547117 is an equidigital number, since it uses as much as digits as its factorization.

13645566547117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9680462.

The product of its digits is 63504000, while the sum is 61.

The spelling of 13645566547117 in words is "thirteen trillion, six hundred forty-five billion, five hundred sixty-six million, five hundred forty-seven thousand, one hundred seventeen".