Base | Representation |
---|---|
bin | 11111000001110000010100… |
… | …010011000100011010010110 |
3 | 122220011110012220201222210200 |
4 | 133001300110103010122112 |
5 | 120341230131104043023 |
6 | 1202120513322201330 |
7 | 40512625016206143 |
oct | 3701602423043226 |
9 | 586143186658720 |
10 | 136460041471638 |
11 | 3a5314189a5315 |
12 | 1337aa53953246 |
13 | 5b1b185470b11 |
14 | 259a9b631b3ca |
15 | 10b998b120743 |
hex | 7c1c144c4696 |
136460041471638 has 24 divisors (see below), whose sum is σ = 298711499720088. Its totient is φ = 45017745639552.
The previous prime is 136460041471627. The next prime is 136460041471657. The reversal of 136460041471638 is 836174140064631.
136460041471638 is a `hidden beast` number, since 1 + 3 + 6 + 4 + 60 + 0 + 414 + 7 + 163 + 8 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 39077902456 + ... + 39077905947.
It is an arithmetic number, because the mean of its divisors is an integer number (12446312488337).
Almost surely, 2136460041471638 is an apocalyptic number.
136460041471638 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
136460041471638 is an abundant number, since it is smaller than the sum of its proper divisors (162251458248450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136460041471638 is a wasteful number, since it uses less digits than its factorization.
136460041471638 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78155808508 (or 78155808505 counting only the distinct ones).
The product of its (nonzero) digits is 6967296, while the sum is 54.
The spelling of 136460041471638 in words is "one hundred thirty-six trillion, four hundred sixty billion, forty-one million, four hundred seventy-one thousand, six hundred thirty-eight".
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