1364720143 has 2 divisors, whose sum is σ = 1364720144. Its totient is φ = 1364720142.

The previous prime is 1364720131. The next prime is 1364720167. The reversal of 1364720143 is 3410274631.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1364720143 is a prime.

It is a super-2 number, since 2×1364720143² = 3724922137419880898, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1364720183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 682360071 + 682360072.

It is an arithmetic number, because the mean of its divisors is an integer number (682360072).

Almost surely, 2^1364720143 is an apocalyptic number.

1364720143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1364720143 is an equidigital number, since it uses as much as digits as its factorization.

1364720143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

The square root of 1364720143 is about 36942.1188212046. The cubic root of 1364720143 is about 1109.2119350174.

Adding to 1364720143 its reverse (3410274631), we get a palindrome (4774994774).

The spelling of 1364720143 in words is "one billion, three hundred sixty-four million, seven hundred twenty thousand, one hundred forty-three".