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13650311452413 = 34550103817471
BaseRepresentation
bin1100011010100011010111…
…1101110001011011111101
31210022221211200020011210010
43012220311331301123331
53242121314212434123
645010511055533433
72606126304630606
oct306506575613375
953287750204703
1013650311452413
114393078a52129
12164563182a279
137802aca630bc
14352970110dad
1518a1213bb993
hexc6a35f716fd

13650311452413 has 4 divisors (see below), whose sum is σ = 18200415269888. Its totient is φ = 9100207634940.

The previous prime is 13650311452399. The next prime is 13650311452433. The reversal of 13650311452413 is 31425411305631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13650311452413 - 28 = 13650311452157 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13650311452433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2275051908733 + ... + 2275051908738.

It is an arithmetic number, because the mean of its divisors is an integer number (4550103817472).

Almost surely, 213650311452413 is an apocalyptic number.

It is an amenable number.

13650311452413 is a deficient number, since it is larger than the sum of its proper divisors (4550103817475).

13650311452413 is an equidigital number, since it uses as much as digits as its factorization.

13650311452413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4550103817474.

The product of its (nonzero) digits is 129600, while the sum is 39.

The spelling of 13650311452413 in words is "thirteen trillion, six hundred fifty billion, three hundred eleven million, four hundred fifty-two thousand, four hundred thirteen".

Divisors: 1 3 4550103817471 13650311452413