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13650335949 = 34550111983
BaseRepresentation
bin11001011011001111…
…11001100011001101
31022020022111220200010
430231213321203031
5210423441222244
610134302023433
7662160640545
oct145547714315
938208456603
1013650335949
115875293488
12278b577b79
131397042883
14936c96325
1554d5b3eb9
hex32d9f98cd

13650335949 has 4 divisors (see below), whose sum is σ = 18200447936. Its totient is φ = 9100223964.

The previous prime is 13650335891. The next prime is 13650335953. The reversal of 13650335949 is 94953305631.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 94953305631 = 331651101877.

It is not a de Polignac number, because 13650335949 - 29 = 13650335437 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13650335898 and 13650335907.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13650335999) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2275055989 + ... + 2275055994.

It is an arithmetic number, because the mean of its divisors is an integer number (4550111984).

Almost surely, 213650335949 is an apocalyptic number.

It is an amenable number.

13650335949 is a deficient number, since it is larger than the sum of its proper divisors (4550111987).

13650335949 is an equidigital number, since it uses as much as digits as its factorization.

13650335949 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4550111986.

The product of its (nonzero) digits is 1312200, while the sum is 48.

The spelling of 13650335949 in words is "thirteen billion, six hundred fifty million, three hundred thirty-five thousand, nine hundred forty-nine".

Divisors: 1 3 4550111983 13650335949