Base | Representation |
---|---|
bin | 111111100100010000… |
… | …0001101101100010111 |
3 | 111001100110122111112211 |
4 | 1333020200031230113 |
5 | 4214032003432241 |
6 | 142413313254251 |
7 | 12601535533102 |
oct | 1771040155427 |
9 | 431313574484 |
10 | 136507874071 |
11 | 52990155258 |
12 | 22558264387 |
13 | cb462516aa |
14 | 686d91d739 |
15 | 383e36c781 |
hex | 1fc880db17 |
136507874071 has 2 divisors, whose sum is σ = 136507874072. Its totient is φ = 136507874070.
The previous prime is 136507874047. The next prime is 136507874093. The reversal of 136507874071 is 170478705631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136507874071 - 29 = 136507873559 is a prime.
It is a super-2 number, since 2×1365078740712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136507874771) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68253937035 + 68253937036.
It is an arithmetic number, because the mean of its divisors is an integer number (68253937036).
Almost surely, 2136507874071 is an apocalyptic number.
136507874071 is a deficient number, since it is larger than the sum of its proper divisors (1).
136507874071 is an equidigital number, since it uses as much as digits as its factorization.
136507874071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 987840, while the sum is 49.
The spelling of 136507874071 in words is "one hundred thirty-six billion, five hundred seven million, eight hundred seventy-four thousand, seventy-one".
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