Base | Representation |
---|---|
bin | 11111000010100001101100… |
… | …000110010110110011001100 |
3 | 122220100112001110102122202010 |
4 | 133002201230012112303030 |
5 | 120343112213330013034 |
6 | 1202201121543501220 |
7 | 40516512512364315 |
oct | 3702415406266314 |
9 | 586315043378663 |
10 | 136513054141644 |
11 | 3a5519521a1994 |
12 | 13389189757810 |
13 | 5b2318340cccb |
14 | 259d3a4bd160c |
15 | 10bb04020d3e9 |
hex | 7c286c196ccc |
136513054141644 has 48 divisors (see below), whose sum is σ = 322394125390848. Its totient is φ = 44952487397568.
The previous prime is 136513054141637. The next prime is 136513054141687. The reversal of 136513054141644 is 446141450315631.
It is a happy number.
136513054141644 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 136513054141593 and 136513054141602.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6877029 + ... + 17897475.
It is an arithmetic number, because the mean of its divisors is an integer number (6716544278976).
Almost surely, 2136513054141644 is an apocalyptic number.
It is an amenable number.
136513054141644 is an abundant number, since it is smaller than the sum of its proper divisors (185881071249204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136513054141644 is a wasteful number, since it uses less digits than its factorization.
136513054141644 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11032974 (or 11032972 counting only the distinct ones).
The product of its (nonzero) digits is 2073600, while the sum is 48.
The spelling of 136513054141644 in words is "one hundred thirty-six trillion, five hundred thirteen billion, fifty-four million, one hundred forty-one thousand, six hundred forty-four".
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