13654315401242 has 4 divisors (see below), whose sum is σ = 20481473101866. Its totient is φ = 6827157700620.

The previous prime is 13654315401169. The next prime is 13654315401263. The reversal of 13654315401242 is 24210451345631.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11130891017401 + 2523424383841 = 3336299^2 + 1588529^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13654315401242.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3413578850309 + ... + 3413578850312.

Almost surely, 2^{13654315401242} is an apocalyptic number.

13654315401242 is a deficient number, since it is larger than the sum of its proper divisors (6827157700624).

13654315401242 is an equidigital number, since it uses as much as digits as its factorization.

13654315401242 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6827157700623.

The product of its (nonzero) digits is 345600, while the sum is 41.

Adding to 13654315401242 its reverse (24210451345631), we get a palindrome (37864766746873).

The spelling of 13654315401242 in words is "thirteen trillion, six hundred fifty-four billion, three hundred fifteen million, four hundred one thousand, two hundred forty-two".