Base | Representation |
---|---|
bin | 1100011010110010010010… |
… | …0111101000000000011011 |
3 | 1210100100011201100212000020 |
4 | 3012230210213220000123 |
5 | 3242203014220314433 |
6 | 45012412250241523 |
7 | 2606330443632036 |
oct | 306544447500033 |
9 | 53310151325006 |
10 | 13654315401243 |
11 | 4394843093150 |
12 | 164636a7262a3 |
13 | 78079a437caa |
14 | 352c2dbb201d |
15 | 18a2a7b71cb3 |
hex | c6b249e801b |
13654315401243 has 16 divisors (see below), whose sum is σ = 19893221815296. Its totient is φ = 8261842911840.
The previous prime is 13654315401169. The next prime is 13654315401263. The reversal of 13654315401243 is 34210451345631.
It is not a de Polignac number, because 13654315401243 - 217 = 13654315270171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13654315401195 and 13654315401204.
It is not an unprimeable number, because it can be changed into a prime (13654315401263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 337473355 + ... + 337513812.
It is an arithmetic number, because the mean of its divisors is an integer number (1243326363456).
Almost surely, 213654315401243 is an apocalyptic number.
13654315401243 is a deficient number, since it is larger than the sum of its proper divisors (6238906414053).
13654315401243 is a wasteful number, since it uses less digits than its factorization.
13654315401243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 674987794.
The product of its (nonzero) digits is 518400, while the sum is 42.
Adding to 13654315401243 its reverse (34210451345631), we get a palindrome (47864766746874).
The spelling of 13654315401243 in words is "thirteen trillion, six hundred fifty-four billion, three hundred fifteen million, four hundred one thousand, two hundred forty-three".
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