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136554211601 is a prime number
BaseRepresentation
bin111111100101101000…
…0111110100100010001
3111001110200211200200122
41333023100332210101
54214130334232401
6142422050400025
712602640434663
oct1771320764421
9431420750618
10136554211601
1152a04324335
122256b890015
13cb52a26a52
146875b42533
15384347221b
hex1fcb43e911

136554211601 has 2 divisors, whose sum is σ = 136554211602. Its totient is φ = 136554211600.

The previous prime is 136554211583. The next prime is 136554211603. The reversal of 136554211601 is 106112455631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136547986576 + 6225025 = 369524^2 + 2495^2 .

It is a cyclic number.

It is not a de Polignac number, because 136554211601 - 210 = 136554210577 is a prime.

Together with 136554211603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (136554211603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68277105800 + 68277105801.

It is an arithmetic number, because the mean of its divisors is an integer number (68277105801).

Almost surely, 2136554211601 is an apocalyptic number.

It is an amenable number.

136554211601 is a deficient number, since it is larger than the sum of its proper divisors (1).

136554211601 is an equidigital number, since it uses as much as digits as its factorization.

136554211601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 136554211601 in words is "one hundred thirty-six billion, five hundred fifty-four million, two hundred eleven thousand, six hundred one".