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13655512093 is a prime number
BaseRepresentation
bin11001011011110111…
…01001010000011101
31022020200020220000011
430231323221100131
5210431302341333
610135005003221
7662252636416
oct145573512035
938220226004
1013655512093
1158781a9393
122791253511
131398135892
1493784280d
1554dc879cd
hex32dee941d

13655512093 has 2 divisors, whose sum is σ = 13655512094. Its totient is φ = 13655512092.

The previous prime is 13655512067. The next prime is 13655512103. The reversal of 13655512093 is 39021555631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9686890084 + 3968622009 = 98422^2 + 62997^2 .

It is an emirp because it is prime and its reverse (39021555631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13655512093 - 29 = 13655511581 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13655512693) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6827756046 + 6827756047.

It is an arithmetic number, because the mean of its divisors is an integer number (6827756047).

Almost surely, 213655512093 is an apocalyptic number.

It is an amenable number.

13655512093 is a deficient number, since it is larger than the sum of its proper divisors (1).

13655512093 is an equidigital number, since it uses as much as digits as its factorization.

13655512093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 121500, while the sum is 40.

The spelling of 13655512093 in words is "thirteen billion, six hundred fifty-five million, five hundred twelve thousand, ninety-three".