Base | Representation |
---|---|
bin | 111111100110001110… |
… | …0011101111100100011 |
3 | 111001112002002002112210 |
4 | 1333030130131330203 |
5 | 4214200421012211 |
6 | 142424034453203 |
7 | 12603300565554 |
oct | 1771434357443 |
9 | 431462062483 |
10 | 136574000931 |
11 | 52a14510355 |
12 | 22576434203 |
13 | cb56b65304 |
14 | 687861432b |
15 | 38450809a6 |
hex | 1fcc71df23 |
136574000931 has 16 divisors (see below), whose sum is σ = 183937471488. Its totient is φ = 90130284000.
The previous prime is 136574000879. The next prime is 136574000933. The reversal of 136574000931 is 139000475631.
It is not a de Polignac number, because 136574000931 - 29 = 136574000419 is a prime.
It is a super-2 number, since 2×1365740009312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 136574000931.
It is not an unprimeable number, because it can be changed into a prime (136574000933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1616520 + ... + 1698906.
It is an arithmetic number, because the mean of its divisors is an integer number (11496091968).
Almost surely, 2136574000931 is an apocalyptic number.
136574000931 is a deficient number, since it is larger than the sum of its proper divisors (47363470557).
136574000931 is a wasteful number, since it uses less digits than its factorization.
136574000931 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87962.
The product of its (nonzero) digits is 68040, while the sum is 39.
The spelling of 136574000931 in words is "one hundred thirty-six billion, five hundred seventy-four million, nine hundred thirty-one", and thus it is an aban number.
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