Base | Representation |
---|---|
bin | 111111100111001010… |
… | …1001011110110010111 |
3 | 111001121021121211201221 |
4 | 1333032111023312113 |
5 | 4214232021134411 |
6 | 142431125031211 |
7 | 12604133556115 |
oct | 1771625136627 |
9 | 431537554657 |
10 | 136605646231 |
11 | 52a3036499a |
12 | 22584b55507 |
13 | cb60595142 |
14 | 687c8d0ab5 |
15 | 3847c32071 |
hex | 1fce54bd97 |
136605646231 has 2 divisors, whose sum is σ = 136605646232. Its totient is φ = 136605646230.
The previous prime is 136605646211. The next prime is 136605646291. The reversal of 136605646231 is 132646506631.
It is a weak prime.
It is an emirp because it is prime and its reverse (132646506631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 136605646231 - 29 = 136605645719 is a prime.
It is a super-2 number, since 2×1366056462312 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136605646211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68302823115 + 68302823116.
It is an arithmetic number, because the mean of its divisors is an integer number (68302823116).
Almost surely, 2136605646231 is an apocalyptic number.
136605646231 is a deficient number, since it is larger than the sum of its proper divisors (1).
136605646231 is an equidigital number, since it uses as much as digits as its factorization.
136605646231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 43.
The spelling of 136605646231 in words is "one hundred thirty-six billion, six hundred five million, six hundred forty-six thousand, two hundred thirty-one".
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