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136627076153 is a prime number
BaseRepresentation
bin111111100111110011…
…0111011110000111001
3111001122202221121001202
41333033212323300321
54214303012414103
6142433212223545
712604513662041
oct1771746736071
9431582847052
10136627076153
1152a41471577
122259016abb5
13cb64b59379
1468816ac721
153849a66988
hex1fcf9bbc39

136627076153 has 2 divisors, whose sum is σ = 136627076154. Its totient is φ = 136627076152.

The previous prime is 136627076141. The next prime is 136627076191. The reversal of 136627076153 is 351670726631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 116327380624 + 20299695529 = 341068^2 + 142477^2 .

It is a cyclic number.

It is not a de Polignac number, because 136627076153 - 24 = 136627076137 is a prime.

It is a super-2 number, since 2×1366270761532 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 136627076098 and 136627076107.

It is not a weakly prime, because it can be changed into another prime (136627076353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68313538076 + 68313538077.

It is an arithmetic number, because the mean of its divisors is an integer number (68313538077).

Almost surely, 2136627076153 is an apocalyptic number.

It is an amenable number.

136627076153 is a deficient number, since it is larger than the sum of its proper divisors (1).

136627076153 is an equidigital number, since it uses as much as digits as its factorization.

136627076153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 952560, while the sum is 47.

The spelling of 136627076153 in words is "one hundred thirty-six billion, six hundred twenty-seven million, seventy-six thousand, one hundred fifty-three".