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136627076141 is a prime number
BaseRepresentation
bin111111100111110011…
…0111011110000101101
3111001122202221121001022
41333033212323300231
54214303012414031
6142433212223525
712604513662023
oct1771746736055
9431582847038
10136627076141
1152a41471566
122259016aba5
13cb64b5936a
1468816ac713
153849a6697b
hex1fcf9bbc2d

136627076141 has 2 divisors, whose sum is σ = 136627076142. Its totient is φ = 136627076140.

The previous prime is 136627076137. The next prime is 136627076153. The reversal of 136627076141 is 141670726631.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 77178396100 + 59448680041 = 277810^2 + 243821^2 .

It is a cyclic number.

It is not a de Polignac number, because 136627076141 - 22 = 136627076137 is a prime.

It is a super-2 number, since 2×1366270761412 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 136627076092 and 136627076101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136627076191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68313538070 + 68313538071.

It is an arithmetic number, because the mean of its divisors is an integer number (68313538071).

Almost surely, 2136627076141 is an apocalyptic number.

It is an amenable number.

136627076141 is a deficient number, since it is larger than the sum of its proper divisors (1).

136627076141 is an equidigital number, since it uses as much as digits as its factorization.

136627076141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 254016, while the sum is 44.

The spelling of 136627076141 in words is "one hundred thirty-six billion, six hundred twenty-seven million, seventy-six thousand, one hundred forty-one".