Base | Representation |
---|---|
bin | 111111101001110011… |
… | …0100100001110100011 |
3 | 111001211110001011212122 |
4 | 1333103212210032203 |
5 | 4214422141313421 |
6 | 142444004414455 |
7 | 12606256403453 |
oct | 1772346441643 |
9 | 431743034778 |
10 | 136694088611 |
11 | 52a76281a73 |
12 | 225aa6a742b |
13 | cb759c0102 |
14 | 688a553d63 |
15 | 38508a22ab |
hex | 1fd39a43a3 |
136694088611 has 2 divisors, whose sum is σ = 136694088612. Its totient is φ = 136694088610.
The previous prime is 136694088593. The next prime is 136694088613. The reversal of 136694088611 is 116880496631.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 136694088611 - 210 = 136694087587 is a prime.
It is a super-2 number, since 2×1366940886112 (a number of 23 digits) contains 22 as substring.
Together with 136694088613, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (136694088613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68347044305 + 68347044306.
It is an arithmetic number, because the mean of its divisors is an integer number (68347044306).
Almost surely, 2136694088611 is an apocalyptic number.
136694088611 is a deficient number, since it is larger than the sum of its proper divisors (1).
136694088611 is an equidigital number, since it uses as much as digits as its factorization.
136694088611 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1492992, while the sum is 53.
The spelling of 136694088611 in words is "one hundred thirty-six billion, six hundred ninety-four million, eighty-eight thousand, six hundred eleven".
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