Base | Representation |
---|---|
bin | 11111000101100100100100… |
… | …100010110011110011000111 |
3 | 122221002112011122200012101122 |
4 | 133011210210202303303013 |
5 | 120410024241100212112 |
6 | 1202441205531344155 |
7 | 40540601136560606 |
oct | 3705444442636307 |
9 | 587075148605348 |
10 | 136722307038407 |
11 | 3a622671a86402 |
12 | 13401847bb205b |
13 | 5b39b206c750c |
14 | 25a9575b19a3d |
15 | 10c16dab66872 |
hex | 7c59248b3cc7 |
136722307038407 has 4 divisors (see below), whose sum is σ = 136753093421376. Its totient is φ = 136691520655440.
The previous prime is 136722307038391. The next prime is 136722307038523. The reversal of 136722307038407 is 704830703227631.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 136722307038407 - 24 = 136722307038391 is a prime.
It is a super-3 number, since 3×1367223070384073 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (136722307035407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15393184823 + ... + 15393193704.
It is an arithmetic number, because the mean of its divisors is an integer number (34188273355344).
Almost surely, 2136722307038407 is an apocalyptic number.
136722307038407 is a deficient number, since it is larger than the sum of its proper divisors (30786382969).
136722307038407 is an equidigital number, since it uses as much as digits as its factorization.
136722307038407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30786382968.
The product of its (nonzero) digits is 7112448, while the sum is 53.
The spelling of 136722307038407 in words is "one hundred thirty-six trillion, seven hundred twenty-two billion, three hundred seven million, thirty-eight thousand, four hundred seven".
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