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136778421253543 is a prime number
BaseRepresentation
bin11111000110011000110101…
…001101100011010110100111
3122221021220000100110200101221
4133012120311031203112213
5120411434201320103133
61202523050030001211
740544625533540506
oct3706306515432647
9587256010420357
10136778421253543
113a644447a9a813
12134106a8646207
135b421c40b2b04
1425ac17a4aa83d
1510c2dc21a5a2d
hex7c66353635a7

136778421253543 has 2 divisors, whose sum is σ = 136778421253544. Its totient is φ = 136778421253542.

The previous prime is 136778421253499. The next prime is 136778421253601. The reversal of 136778421253543 is 345352124877631.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-136778421253543 is a prime.

It is a super-2 number, since 2×1367784212535432 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (136778421253043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68389210626771 + 68389210626772.

It is an arithmetic number, because the mean of its divisors is an integer number (68389210626772).

Almost surely, 2136778421253543 is an apocalyptic number.

136778421253543 is a deficient number, since it is larger than the sum of its proper divisors (1).

136778421253543 is an equidigital number, since it uses as much as digits as its factorization.

136778421253543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 101606400, while the sum is 61.

The spelling of 136778421253543 in words is "one hundred thirty-six trillion, seven hundred seventy-eight billion, four hundred twenty-one million, two hundred fifty-three thousand, five hundred forty-three".