Base | Representation |
---|---|
bin | 11111000110011000110101… |
… | …001101100011010110100111 |
3 | 122221021220000100110200101221 |
4 | 133012120311031203112213 |
5 | 120411434201320103133 |
6 | 1202523050030001211 |
7 | 40544625533540506 |
oct | 3706306515432647 |
9 | 587256010420357 |
10 | 136778421253543 |
11 | 3a644447a9a813 |
12 | 134106a8646207 |
13 | 5b421c40b2b04 |
14 | 25ac17a4aa83d |
15 | 10c2dc21a5a2d |
hex | 7c66353635a7 |
136778421253543 has 2 divisors, whose sum is σ = 136778421253544. Its totient is φ = 136778421253542.
The previous prime is 136778421253499. The next prime is 136778421253601. The reversal of 136778421253543 is 345352124877631.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-136778421253543 is a prime.
It is a super-2 number, since 2×1367784212535432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (136778421253043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68389210626771 + 68389210626772.
It is an arithmetic number, because the mean of its divisors is an integer number (68389210626772).
Almost surely, 2136778421253543 is an apocalyptic number.
136778421253543 is a deficient number, since it is larger than the sum of its proper divisors (1).
136778421253543 is an equidigital number, since it uses as much as digits as its factorization.
136778421253543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 101606400, while the sum is 61.
The spelling of 136778421253543 in words is "one hundred thirty-six trillion, seven hundred seventy-eight billion, four hundred twenty-one million, two hundred fifty-three thousand, five hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.085 sec. • engine limits •