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136784074267067 is a prime number
BaseRepresentation
bin11111000110011110000110…
…001010000101100110111011
3122221022102121022121112010012
4133012132012022011212323
5120412032241003021232
61202525423005412135
740545215605422503
oct3706360612054673
9587272538545105
10136784074267067
113a646888a74517
121341180586a04b
135b428b530c226
1425ac555194a03
1510c31035ec9b2
hex7c67862859bb

136784074267067 has 2 divisors, whose sum is σ = 136784074267068. Its totient is φ = 136784074267066.

The previous prime is 136784074267007. The next prime is 136784074267069. The reversal of 136784074267067 is 760762470487631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 136784074267067 - 244 = 119191888222651 is a prime.

Together with 136784074267069, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 136784074266988 and 136784074267006.

It is not a weakly prime, because it can be changed into another prime (136784074267069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68392037133533 + 68392037133534.

It is an arithmetic number, because the mean of its divisors is an integer number (68392037133534).

Almost surely, 2136784074267067 is an apocalyptic number.

136784074267067 is a deficient number, since it is larger than the sum of its proper divisors (1).

136784074267067 is an equidigital number, since it uses as much as digits as its factorization.

136784074267067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 398297088, while the sum is 68.

The spelling of 136784074267067 in words is "one hundred thirty-six trillion, seven hundred eighty-four billion, seventy-four million, two hundred sixty-seven thousand, sixty-seven".