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1368047167757 is a prime number
BaseRepresentation
bin10011111010000101111…
…101110010100100001101
311211210011120002201212122
4103322011331302210031
5134403230033332012
62524245554342325
7200560325026514
oct23720575624415
94753146081778
101368047167757
11488204a63516
121a117828a9a5
139c010aa094a
144a2dcaa367b
15258bcd8de72
hex13e85f7290d

1368047167757 has 2 divisors, whose sum is σ = 1368047167758. Its totient is φ = 1368047167756.

The previous prime is 1368047167727. The next prime is 1368047167777. The reversal of 1368047167757 is 7577617408631.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1110618791881 + 257428375876 = 1053859^2 + 507374^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1368047167757 is a prime.

It is a super-2 number, since 2×13680471677572 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1368047167757.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1368047167727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 684023583878 + 684023583879.

It is an arithmetic number, because the mean of its divisors is an integer number (684023583879).

Almost surely, 21368047167757 is an apocalyptic number.

It is an amenable number.

1368047167757 is a deficient number, since it is larger than the sum of its proper divisors (1).

1368047167757 is an equidigital number, since it uses as much as digits as its factorization.

1368047167757 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41489280, while the sum is 62.

The spelling of 1368047167757 in words is "one trillion, three hundred sixty-eight billion, forty-seven million, one hundred sixty-seven thousand, seven hundred fifty-seven".