Base | Representation |
---|---|
bin | 111111101111101111… |
… | …1010111010110011010 |
3 | 111002100100022201112022 |
4 | 1333133133113112122 |
5 | 4220324220334300 |
6 | 142515451214442 |
7 | 12614230533011 |
oct | 1773737272632 |
9 | 432310281468 |
10 | 136893527450 |
11 | 53068911359 |
12 | 22645447422 |
13 | cba810bb64 |
14 | 68a8c2ba78 |
15 | 386314a285 |
hex | 1fdf7d759a |
136893527450 has 12 divisors (see below), whose sum is σ = 254621961150. Its totient is φ = 54757410960.
The previous prime is 136893527413. The next prime is 136893527483. The reversal of 136893527450 is 54725398631.
It is a happy number.
It can be written as a sum of positive squares in 3 ways, for example, as 66397436329 + 70496091121 = 257677^2 + 265511^2 .
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 136893527392 and 136893527401.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1368935225 + ... + 1368935324.
It is a 1-persistent number, because it is pandigital, but 2⋅136893527450 = 273787054900 is not.
Almost surely, 2136893527450 is an apocalyptic number.
136893527450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
136893527450 is a deficient number, since it is larger than the sum of its proper divisors (117728433700).
136893527450 is a wasteful number, since it uses less digits than its factorization.
136893527450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2737870561 (or 2737870556 counting only the distinct ones).
The product of its (nonzero) digits is 5443200, while the sum is 53.
The spelling of 136893527450 in words is "one hundred thirty-six billion, eight hundred ninety-three million, five hundred twenty-seven thousand, four hundred fifty".
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