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136893527450 = 2522737870549
BaseRepresentation
bin111111101111101111…
…1010111010110011010
3111002100100022201112022
41333133133113112122
54220324220334300
6142515451214442
712614230533011
oct1773737272632
9432310281468
10136893527450
1153068911359
1222645447422
13cba810bb64
1468a8c2ba78
15386314a285
hex1fdf7d759a

136893527450 has 12 divisors (see below), whose sum is σ = 254621961150. Its totient is φ = 54757410960.

The previous prime is 136893527413. The next prime is 136893527483. The reversal of 136893527450 is 54725398631.

It is a happy number.

It can be written as a sum of positive squares in 3 ways, for example, as 66397436329 + 70496091121 = 257677^2 + 265511^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 136893527392 and 136893527401.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1368935225 + ... + 1368935324.

It is a 1-persistent number, because it is pandigital, but 2⋅136893527450 = 273787054900 is not.

Almost surely, 2136893527450 is an apocalyptic number.

136893527450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

136893527450 is a deficient number, since it is larger than the sum of its proper divisors (117728433700).

136893527450 is a wasteful number, since it uses less digits than its factorization.

136893527450 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2737870561 (or 2737870556 counting only the distinct ones).

The product of its (nonzero) digits is 5443200, while the sum is 53.

The spelling of 136893527450 in words is "one hundred thirty-six billion, eight hundred ninety-three million, five hundred twenty-seven thousand, four hundred fifty".

Divisors: 1 2 5 10 25 50 2737870549 5475741098 13689352745 27378705490 68446763725 136893527450